80y^2+4y-4=

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Solution for 80y^2+4y-4= equation:


Simplifying
80y2 + 4y + -4 = 0

Reorder the terms:
-4 + 4y + 80y2 = 0

Solving
-4 + 4y + 80y2 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), '4'.
4(-1 + y + 20y2) = 0

Factor a trinomial.
4((-1 + -4y)(1 + -5y)) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(-1 + -4y)' equal to zero and attempt to solve: Simplifying -1 + -4y = 0 Solving -1 + -4y = 0 Move all terms containing y to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -4y = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -4y = 0 + 1 -4y = 0 + 1 Combine like terms: 0 + 1 = 1 -4y = 1 Divide each side by '-4'. y = -0.25 Simplifying y = -0.25

Subproblem 2

Set the factor '(1 + -5y)' equal to zero and attempt to solve: Simplifying 1 + -5y = 0 Solving 1 + -5y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -5y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -5y = 0 + -1 -5y = 0 + -1 Combine like terms: 0 + -1 = -1 -5y = -1 Divide each side by '-5'. y = 0.2 Simplifying y = 0.2

Solution

y = {-0.25, 0.2}

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